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19n^2-37n-2=0
a = 19; b = -37; c = -2;
Δ = b2-4ac
Δ = -372-4·19·(-2)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-39}{2*19}=\frac{-2}{38} =-1/19 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+39}{2*19}=\frac{76}{38} =2 $
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